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| The Outdoors Advice Blog |
The second angle of a triangular building lot is three times as large as the first. The third angle is 10° mor?
The second angle of a triangular building lot is three times as large as the first. The third angle is 10° more than the sum of the other two angles. Find the measure of the third angle.
X-angle 1
3x-angle 2 (ang2 is 3 times larger than ang1)
3x+x+10-angle 3 (ang 3 is 10th more than ang1&2 sum)
All triangles equal 180.
Equation: x+3x+(3x+x+10)=180
Combine like terms (x)
8x+10=180
Subtract 10.
8x=170
Divide by 8
X=21.25 (theres angle 1)
Find angle 2. So multiple.
21.25x3=63.75(there's angle 2)
Add them together, then add 10 for angle 3.
21.25+63.75+10=95 (theres angle 3)
Check it.
95+63.75+21.25=180
Solved
